- April 6, 2008
- 3 (after 3 ratings)
A simple adaptation of RegistrationFormUniqueEmail from django-registration http://code.google.com/p/django-registration to allow users to register without using a username. This works great with the code from this comment: http://www.djangosnippets.org/snippets/74/#c195 to allow users to completely eliminate the need for a username.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
class RegistrationFormNoUserName(RegistrationFormUniqueEmail): """ A registration form that only requires the user to enter their e-mail address and password. The username is automatically generated This class requires django-registration to extend the RegistrationFormUniqueEmail """ username = forms.CharField(widget=forms.HiddenInput, required=False) def clean_username(self): "This function is required to overwrite an inherited username clean" return self.cleaned_data['username'] def clean(self): if not self.errors: self.cleaned_data['username'] = '%s%s' % (self.cleaned_data['email'].split('@',1), User.objects.count()) super(RegistrationFormNoUserName, self).clean() return self.cleaned_data
More like this
- Stuff by NixonDash 1 month ago
- Add custom fields to the built-in Group model by jmoppel 3 months, 1 week ago
- Month / Year SelectDateWidget based on django SelectDateWidget by pierreben 6 months, 3 weeks ago
- Python Django CRUD Example Tutorial by tuts_station 7 months, 1 week ago
- Browser-native date input field by kytta 8 months, 3 weeks ago
I updated the username generation a little... Didn't really like the solution with the total user count.
Actually the code in my last comment was buggy. Working version:
The solution above will only work the first time a duplicate is found. For example, if [email protected] registers, his username will be "joe". If [email protected] tries to register, it will find "joe" and will get a count of 1 and username will be "joe2". However, if [email protected] tries to register, the local part will be "joe". It will still get a count of 1 and it will try to set username to joe2 and your application will get an error. This is because filter is "username=joe" (thus, not finding "joe2"). A better solution, and one that will prevent this error is:
c = User.objects.filter(username__startswith=localpart).count()
Please login first before commenting.