This filter allows you to format numbers like PHP's number_format function.
If var
equals 1234.567{{ var|number_format:2 }}
produces 1,234.56.
Because Django's template filters support just 1 argument you'll have to adjust the argument's default values by hand until #1199 is fixed.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 | from django import template
register = template.Library()
def number_format(number, decimals=0, dec_point='.', thousands_sep=','):
try:
number = round(float(number), decimals)
except ValueError:
return number
neg = number < 0
integer, fractional = str(abs(number)).split('.')
m = len(integer) % 3
if m:
parts = [integer[:m]]
else:
parts = []
parts.extend([integer[m+t:m+t+3] for t in xrange(0, len(integer[m:]), 3)])
if decimals:
return '%s%s%s%s' % (
neg and '-' or '',
thousands_sep.join(parts),
dec_point,
fractional.ljust(decimals, '0')[:decimals]
)
else:
return '%s%s' % (neg and '-' or '', thousands_sep.join(parts))
register.filter(number_format)
|
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