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sqlallall.py

Author:
jkl
Posted:
July 21, 2007
Language:
Python
Version:
.96
Score:
0 (after 0 ratings)

A simple script to run 'manage.py sqlall' on every app in a project.

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#!/usr/bin/env python

import settings
import os

def get_app_name(app_str):
    if '.' in app_str:
        return app_str.rsplit('.', 1)[-1]
    return app_str

apps = [get_app_name(app) for app in settings.INSTALLED_APPS]
for app in apps:
    os.system('python manage.py sqlall %s' % app)

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