Admin Image Widget(snippet 934) with easy-thumbnails
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 | from django.contrib.admin.widgets import AdminFileWidget
from django.utils.translation import ugettext as _
from django.utils.safestring import mark_safe
from django.conf import settings
from PIL import Image
import os
try:
from easy_thumbnails.files import get_thumbnailer
def thumbnail(image_path):
thumbnailer = get_thumbnailer(image_path)
thumbnail_options = {'crop': True, 'size': (160, 120), 'detail': True, 'upscale':True }
t=thumbnailer.get_thumbnail(thumbnail_options)
media_url = settings.MEDIA_URL
return u'<img src="%s%s" alt="%s" width="160" height="120"/>' % (media_url, t, image_path)
except ImportError:
def thumbnail(image_path):
absolute_url = os.path.join(settings.MEDIA_ROOT, image_path)
return u'<img src="%s" alt="%s" />' % (absolute_url, image_path)
class AdminImageWidget(AdminFileWidget):
"""
A FileField Widget that displays an image instead of a file path
if the current file is an image.
"""
def render(self, name, value, attrs=None):
output = []
file_name = str(value)
if file_name:
file_path = '%s%s' % (settings.MEDIA_URL, file_name)
try: # is image
Image.open(os.path.join(settings.MEDIA_ROOT, file_name))
output.append('<a target="_blank" href="%s">%s</a>' % \
(file_path, thumbnail(file_name),))
except IOError: # not image
output.append('%s <a target="_blank" href="%s">%s</a> <br />%s ' % \
(_('Currently:'), file_path, file_name, _('Change:')))
output.append(super(AdminFileWidget, self).render(name, value, attrs))
return mark_safe(u''.join(output))
|
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Comments
There is a small bug in your code, line 18 must call settings.MEDIA_URL instead of settings.MEDIA_ROOT or it won't show the image
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