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Quickly create an admin interface for an app.

Author:
bartTC
Posted:
August 29, 2010
Language:
Python
Version:
1.2
Tags:
models admin legacy
Score:
5 (after 5 ratings)

This creates an admin interface for each model in the "your_appname" app. It also adds each column to the admin list view.

Place this in the admin.py of "your_appname".

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from django.contrib import admin
from django.db.models.loading import get_models, get_app

class DynamicColumnAdmin(admin.ModelAdmin):
    def __init__(self, *args, **kwargs):
        super(DynamicColumnAdmin, self).__init__(*args, **kwargs)
        field_list = [i.name for i in self.model._meta.fields]
        self.list_display = field_list
        self.list_display_links = field_list[0]

for model in get_models(get_app('your_appname')):
    admin.site.register(model, DynamicColumnAdmin)

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