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Custom ImageField filename

Author:
allieus
Posted:
June 17, 2010
Language:
Python
Version:
Not specified
Tags:
Score:
2 (after 2 ratings)

Custom ImageField filename

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def upload_to(instance, filename):
    format = 'photo/%Y/%m/%d/%H%M%S'
    prefix = os.path.normpath(force_unicode(datetime.datetime.now().strftime(smart_str(format))))
    postfix = '%s%s' % (
        string.join(random.sample(string.ascii_letters + string.digits, 5), ''),
        os.path.splitext(filename)[-1],
    )
    filepath = '%s_%s' % (prefix, postfix)
    return filepath


class Test(models.Model):
    photo = models.ImageField(upload_to=upload_to)

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