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Audit word filter

Author:
shinyzhu
Posted:
February 10, 2010
Language:
Python
Version:
1.1
Score:
0 (after 0 ratings)

a simple bad word filter. usage:

{{ post.content|audit }}

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from django import template
from post.models import AuditWord
from datetime import datetime

register = template.Library()

_bad_words = [aw.word for aw in AuditWord.objects.filter(is_published=True)]

@register.filter
def audit(value):
    for word in _bad_words:
        if word in value:
            value = value.replace(word,'*')

    return value

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