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Dynamically create Django admin actions

Author:
pantsman
Posted:
December 14, 2009
Language:
Python
Version:
1.1
Score:
4 (after 4 ratings)

With this snippet, I made a set of admin actions for assigning Quality objects to Package objects.

The Django docs for ModelAdmin.get_actions explain the dictionary of tuples that is returned.

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def create_action(quality):
    def action(modeladmin, request, queryset): queryset.update(quality=quality)
    name = "mark_%s" % (quality,)
    return (name, (action, name, "Mark selected as %s quality" % (quality,)))

class PackageAdmin(admin.ModelAdmin):
    list_display = ('name', 'quality')
            
    def get_actions(self, request):
        return dict(create_action(q) for q in models.Quality.objects.all())

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Comments

mssobhan (on April 24, 2011):

Thanks for the help.

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