- Author:
- arthurfurlan
- Posted:
- April 28, 2009
- Language:
- Python
- Version:
- 1.0
- Score:
- 2 (after 2 ratings)
Get the referer view of a request.
Example:
def some_view(request):
...
referer_view = get_referer_view(request)
return HttpResponseRedirect(referer_view, '/accounts/login/')
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 | # -*- coding: utf-8 -*-
#
# Copyright (c) 2009 Arthur Furlan <[email protected]>
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# On Debian systems, you can find the full text of the license in
# /usr/share/common-licenses/GPL-2
import re
def get_referer_view(request, default=None):
'''
Return the referer view of the current request
Example:
def some_view(request):
...
referer_view = get_referer_view(request)
return HttpResponseRedirect(referer_view, '/accounts/login/')
'''
# if the user typed the url directly in the browser's address bar
referer = request.META.get('HTTP_REFERER')
if not referer:
return default
# remove the protocol and split the url at the slashes
referer = re.sub('^https?:\/\/', '', referer).split('/')
if referer[0] != request.META.get('SERVER_NAME'):
return default
# add the slash at the relative path's view and finished
referer = u'/' + u'/'.join(referer[1:])
return referer
|
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