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soaplib service integration 2

Author:
erny
Posted:
March 30, 2009
Language:
Python
Version:
1.0
Tags:
soap soaplib wsdl
Score:
0 (after 0 ratings)

Based on our first version of soaplib service integration, this second one adds Basic Auth with credentials specified in settings.

It can be tested with django soaplib test cliente

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import base64
from soaplib.wsgi_soap import SimpleWSGISoapApp
from soaplib.service import soapmethod
from soaplib.serializers import primitive as soap_types
soap_types, soapmethod    # make pyflakes happy

from django.conf import settings
from django.http import HttpResponse


def extract_basic_credentials(request):
    """Extact authorization basic credentials from request"""
    username, password = None, None
    if 'HTTP_AUTHORIZATION' in request.META:
        auth = request.META['HTTP_AUTHORIZATION'].split()
        if len(auth) == 2:
            if auth[0].lower() == "basic":
                username, password = base64.b64decode(auth[1]).split(':')
    return username, password


class Http401(Exception):
    pass


class Http403(Exception):
    pass


class DjangoSoapApp(SimpleWSGISoapApp):
    """Adaptor class for handling soaplib webservices."""

    def authenticate(self, request):
        """Authenticate webservice requesta."""
        ws_username = getattr(settings, 'WS_USERNAME', None)
        if ws_username:
            ws_password = getattr(settings, 'WS_PASSWORD', None)
            username, password = extract_basic_credentials(request)
            if username == None:
                raise Http401("401 Authentication required.")
            if username != ws_username or password != ws_password:
                raise Http403("403 You're not authorized to use this webservice!")

    def __call__(self, request):
        """Invoke a webservice request."""
        self.authenticate(request)
        django_resp = HttpResponse()

        def start_response(status, headers):
            status, reason = status.split(' ', 1)
            django_resp.status_code = int(status)
            for header, value in headers:
                django_resp[header] = value

        response = super(SimpleWSGISoapApp, self).__call__(
            request.META, start_response)
        if django_resp.status_code == 405:
            return HttpResponse("405 Method not allowed for this webservice.",
                'text/plain', status=405)

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