- Author:
- limodou
- Posted:
- February 25, 2007
- Language:
- Python
- Version:
- Pre .96
- Score:
- 4 (after 6 ratings)
How to use it
{% pycall os.path.abspath(".") %}
{% pycall os.path.abspath(".") as path %}
This is the {{ path }}.
Syntax
{% pycall module.function(...) [as variable_name] %}
If there is no as variable_name, the result will be output directly.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 | from django import template
from django.utils.translation import gettext_lazy as _
import re
register = template.Library()
r_identifers = re.compile(r'[\w.]+')
class PyCallNode(template.Node):
def __init__(self, expr_string, var_name):
self.expr_string = expr_string
self.var_name = var_name
def __repr__(self):
return "<PyCall node>"
def render(self, context):
clist = list(context)
clist.reverse()
d = {}
d['_'] = _
for c in clist:
d.update(c)
m = r_identifers.match(self.expr_string)
if m:
module, func = m.group().rsplit('.', 1)
funcstring = self.expr_string[len(module) + 1:]
mod = __import__(module, {}, {}, [''])
d[func] = getattr(mod, func)
else:
raise template.TemplateSyntaxError, "The arguments of %r tag should be module.function(...)" % 'pycall'
if self.var_name:
context[self.var_name] = eval(funcstring, d)
return ''
else:
return str(eval(funcstring, d))
def do_pycall(parser, token):
try:
tag_name, arg = token.contents.split(None, 1)
except ValueError:
raise template.TemplateSyntaxError, "%r tag requires arguments" % token.contents[0]
m = re.search(r'(.*?)\s+as\s+(\w+)', arg)
if m:
expr_string, var_name = m.groups()
else:
if not arg:
raise template.TemplateSyntaxError, "The arguments of %r tag should be module.function(...)" % tag_name
expr_string, var_name = arg, None
return PyCallNode(expr_string, var_name)
do_pycall = register.tag("pycall", do_pycall)
|
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Comments
Good programmers don't use
eval
;-) Rest of them had to heavy childhood.#
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