- Author:
- SmileyChris
- Posted:
- October 18, 2009
- Language:
- Python
- Version:
- 1.1
- Score:
- 7 (after 7 ratings)
Nicely output all form errors in one block, using field labels rather than the field attribute names.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | from django import template
from django import forms
from django.forms.forms import NON_FIELD_ERRORS
from django.forms.util import ErrorDict
register = template.Library()
@register.filter
def nice_errors(form, non_field_msg='General form errors'):
nice_errors = ErrorDict()
if isinstance(form, forms.BaseForm):
for field, errors in form.errors.items():
if field == NON_FIELD_ERRORS:
key = non_field_msg
else:
key = form.fields[field].label
nice_errors[key] = errors
return nice_errors
|
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Comments
Example?
#
Example:
(My line-formatting is going to get wiped out by the Markdown processor, so you'll have to paste this into an editor and do indenting there.)
` {% if form.errors %}<br /> <br />
{% with form|nice_errors as qq %} {% for error_name,desc in qq.items %}- {{ error_name }}:
- {{ desc }}
{% endfor %}
{% endwith %}<br /> {% endif %} <br /> `
Since ErrorDict does some auto-HTMLizing of the dict values, this will produce doubly-nested unordered lists.
#
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