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linebreaksli template filter

Author:
rokclimb15
Posted:
June 20, 2007
Language:
Python
Version:
.96
Score:
0 (after 0 ratings)

This template filter will split a string of text on newlines and return a string of <li></li>s with a newline before every line.

This is handy for taking a paragraph of text and making an <ol> or <ul> from its lines.

Don't forget to register your filter with the template library first or the filter won't work.

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import re, string

def linebreaksli(value):
    "Converts strings with newlines into <li></li>s"
    value = re.sub(r'\r\n|\r|\n', '\n', value) # normalize newlines
    lines = re.split('\n', value)
    lines = ['<li>%s</li>' % line for line in lines]
    return '\n'.join(lines)

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