- March 11, 2011
- Not specified
- fcgi prefork flup
- 0 (after 0 ratings)
FastCGI handler in prefork mode first imports every application, then forks. If any application during import opens connection to database, open connection is inherited by all of child processes; open db connection cannot be shared between processes, and if one process sends a request, another can receive a reply; also, if one process closes it, others have a desynchronized database handle.
See: http://stackoverflow.com/questions/1573579/psycopg2-disconnects-from-server http://stackoverflow.com/questions/393637/django-fastcgi-randomly-raising-operationalerror http://code.djangoproject.com/ticket/13215 http://groups.google.com/group/django-users/browse_thread/thread/2c7421cdb9b99e48
If you put this snippet in your project-level init.py, then running manage.py runfcgi will fail loudly if the database connection is open in the parent process. This will happen only when you provide debug=true option to runfcgi to avoid monkey-patching code that runs in production mode.
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# monkey-patch flup to fail loudly if database connection is open when # preforked child starts - but ONLY when debug=true, so that we don't # use monkey-patch on production. import sys if 'runfcgi' in sys.argv and 'debug=true' in sys.argv: from flup.server.preforkserver import PreforkServer def _spawnChild(self, sock): from django.db import connection if connection.connection is not None: raise Exception('''Django database connection is open. This MAY NOT happen.''') return self._spawnChild_orig(sock) PreforkServer._spawnChild_orig = PreforkServer._spawnChild PreforkServer._spawnChild = _spawnChild
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