This is an extension of the fantastic snippet "Compact list_filter" written by onlinehero. Follow his instructions for the installation. My version add the number of filtered objects beside the label of the filters defined by the list_filter property.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 | from django.contrib.admin.filterspecs import FilterSpec, ChoicesFilterSpec
from django.utils.encoding import smart_unicode
from django.db.models import Count
class CustomChoiceFilterSpec(ChoicesFilterSpec):
def __init__(self, f, request, params, model, model_admin):
super(CustomChoiceFilterSpec, self).__init__(f, request, params, model, model_admin)
self.lookup_kwarg = '%s__id__exact' % f.name # Change this to match the search of your object
self.lookup_val = request.GET.get(self.lookup_kwarg, None)
self.objects = model.objects.all()
self.foreign_key = f.name
self.foreign_key_count = {}
for item in model.objects.values(f.name).annotate(count=Count('pk')):
self.foreign_key_count[item[f.name]] = item['count']
def choices(self, cl):
yield {'selected': self.lookup_val is None,
'query_string': cl.get_query_string({}, [self.lookup_kwarg]),
'display': ('All')}
items = set([getattr(i, self.foreign_key) for i in self.objects])
for k in items:
if k is None:
kk = None
else:
kk = k.id
yield {'selected': smart_unicode(k) == self.lookup_val,
'query_string': cl.get_query_string({self.lookup_kwarg: kk}), # Change .id to match what you are searching for
'display': '%s (%s)' % (k, self.foreign_key_count[kk])}
FilterSpec.filter_specs.insert(0, (lambda f: getattr(f, 'compact_filter', False), CustomChoiceFilterSpec))
|
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