# admin.py
# The list of objects can get extremely long. This method will
# override the filter-method for objects by specifying an extra
# attribute on the list of choices, thus only displaying a filter
# method to those objects actually existing in the database.
class CustomChoiceFilterSpec(ChoicesFilterSpec):
def __init__(self, f, request, params, model, model_admin):
super(CustomChoiceFilterSpec, self).__init__(f, request, params, model, model_admin)
self.lookup_kwarg = '%s__id__exact' % f.name # Change this to match the search of your object
self.lookup_val = request.GET.get(self.lookup_kwarg, None)
self.objects = model.objects.all()
def choices(self, cl):
yield {'selected': self.lookup_val is None,
'query_string': cl.get_query_string({}, [self.lookup_kwarg]),
'display': _('All')}
# Filter the call - change i.item to whatever you are filtering on
items = [i.item for i in self.objects]
for k in items:
yield {'selected': smart_unicode(k) == self.lookup_val,
'query_string': cl.get_query_string({self.lookup_kwarg: k.id}), # Change .id to match what you are searching for
'display': k}
FilterSpec.filter_specs.insert(0, (lambda f: getattr(f, 'compact_filter', False), CustomChoiceFilterSpec))
# models.py
# This is just an example
origin = models.CharField(max_length=2, choices=COUNTRIES, verbose_name='Country of origin')
# Add this to the item
origin.compact_filter = True
Comments
Hi onlinehero,
thank you very much for your fantastic snippets. In my Django installation (1.1) it seems that your code had a bug. I changed the line number 20 in this way (items = set([i.item for i in self.objects])). I also make some changes to add a counter beside the label of the filter and to manage objects without foreignkey value set.
You can find below my code:
#
I've made a generic version here: #2644
Works for my case, I think it should cover others' too.
#