Django snippets: Pagination shortcut

def paginate(request, objects, count=10, param_name='page'):
    """
    Shortcut for paginating by some object
    """
    paginator = Paginator(objects, count)

    try:
        pagenum = int(request.GET.get('%s' % param_name, '1'))
    except ValueError:
        pagenum = 1
    
    try:
        result = paginator.page(pagenum)
    except (EmptyPage, InvalidPage):
        result = paginator.page(paginator.num_pages)
    
    return result

More like this

Extend generic view object_list to support paginate_by via cookies by kersurk 2 years, 4 months ago
Lazily lookup dynamically for templates by axiak 5 years, 2 months ago
GlobalRequest middleware by myq 5 months, 4 weeks ago
Paginator Tag for 1.x by HM 4 years, 2 months ago
Other approach of making middleware (by decorators) by diverman 2 years, 2 months ago

This is a function wrapping the code from example from django docs.

The required parameters are: request which is a Request object from a view, and objects - a list of objects to paginate.

You may want to tune number of items per page by specifying count and the name of a GET parameter through param_name

To use it in your view just wrap the paginated object into a function for example:

def someview(request):
    articles = Article.objects.all()
    ... some other logics ...
    return render_to_response(template, {'articles': paginate(request, articles)}

Author:: piratus
Posted:: February 27, 2009
Language:: Python
Django Version:: 1.0
Tags:: pagination
Score:: 1 (after 1 ratings)

Django snippets

Pagination shortcut

More like this

Tools

Comments

Snippets

About